User talk:Cmglee/archive2015

Template:Blakey 65moll.jpg K/T impact site has been nominated for deletion. You are invited to comment on the discussion at the template's entry on the Templates for discussion page. Herostratus (talk) 17:04, 19 February 2015 (UTC)[reply]

Thank you very much for this graph. I was wondering if you would be willing to do a variant to illustrate the important point that deaths are not well predicted by earthquake size (even if you take into account tsunamis)? Since there are many very deadly earthquakes with a moment magnitude of <8, this doesn't show it as clearly as it might. A graph that showed that population density and earthquake preparedness have major and opposite effects on the number of deaths would also be very useful. Apart form off-wiki uses, it could be used in

• List_of_natural_disasters_by_death_toll#52_deadliest_earthquakes
• Earthquake#Human_impacts
• and some of the various pages on earthquake engineering and preparedness

HLHJ (talk) 22:06, 13 March 2015 (UTC)[reply]

Thanks, HLHJ. That's an interesting idea. I think such an illustration is appropriate for an article specifically describing the correlation between death toll and population density/preparedness. Do you have one such article? If so, do you have data from a reputable source? Finally, good catch on the axis labels. I'll update it if I manage to get my Perl interpreter working; I've moved on to Python. cmɢʟee⎆τaʟκ 14:19, 15 March 2015 (UTC)[reply]

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Hi Cmglee, I would like to use your diagram Olympus mons vergleich en.svg - http://commons.wikimedia.org/wiki/File:Olympus_mons_vergleich_en.svg. For a Scholastic book called, "Discovering Mars". We will be happy to credit your diagram, Cmglee/Wikipedia. The book will be available in September 2015. Please email me for more details, [email protected]. Thank you! Emily researcher (talk) 04:13, 20 March 2015 (UTC)Emily researcher[reply]

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David.daileyatsrudotedu (talk) 21:07, 6 April 2015 (UTC) Hi I edit Wikipedia so infrequently that I'm not sure if this will work or not. CMG Lee, I am completely impressed with your example at SVG animation at http://en.wikipedia.org/wiki/SVG_animation#/media/File:Toy_train_SMIL.svg . I am wondering if we can chat at length through e-mail. I'm talking with W3C and Wikipedia about extending SVG functionality and perhaps you can talk at a conference? [email protected][reply]

Many thanks, David. I am honored by your invitation. I had wanted to speak about my work with dynamic (interactive and animated) SVG creation at Wikimania 2015 but missed the scholarship deadline. In case you'd like to see some of my other ideas, I wrote up a short sections on

• my talk page, and
• a local meetup page.

I'll be glad to participate in your talks with W3C and Wikipedia, and collaborate with editors who wish to develop more dynamic SVG. If it's ok with you, can we keep the discussion in this section for now? (I've moved your message here to keep the thread together.) Cheers! cmɢʟee⎆τaʟκ 23:37, 6 April 2015 (UTC)[reply]

David.daileyatsrudotedu (talk) 17:02, 7 April 2015 (UTC) Hi again, yes the conference is September 23-26 in Pittsburgh. https://www.graphicalweb.org/2015/ See also the discussion at https://lists.w3.org/Archives/Public/www-svg/2015Mar/ (under the threads entitled Interactive Declarative Animation in <img>) Also, see http://www.svgopen.org/2009/presentations/50-SVG_in_Wikipedia_and_Wikimedia_Commons/index.pdf and http://www.w3.org/Graphics/SVG/IG/resources/svgprimer.html (it has some material on interactive SVG) I think I share your objectives here of using high quality animated and interactive graphics for illustration, explanation and education! -- here are a couple of other things vaguely reminiscent of your trains example: https://ello.co/ddailey/post/hynvB12pPA9wiYzvU0c9jQ and https://ello.co/ddailey/post/NLBLXkTIIYGiyrE4xVW3IA . Concerning Venn and Euler diagrams (I think I saw you had done something along those lines) see https://ello.co/ddailey/post/aaLse3NTZd6YS4ty3xJE3A Cheers! ( I don't seem to be able to get notifications here when a reply is made despite flagging it as "watched" -- so email might be more reliable;) ) David.daileyatsrudotedu (talk) 17:04, 5 May 2015 (UTC) Hello again. May 18th is the deadline for submitting something for the conference. Would love to see you submit something![reply]

Thanks, David. I've sent you an email at [email protected]. Cheers, cmɢʟee⎆τaʟκ 23:02, 10 May 2015 (UTC)[reply]

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Would be a lot more informative if both axes were log, instead of just the x axis. Dicklyon (talk) 23:37, 9 April 2015 (UTC)[reply]

That was quick, Dicklyon! Good idea — I'll see what I can come up with this weekend... cmɢʟee⎆τaʟκ 00:46, 10 April 2015 (UTC)[reply]

		The E=mc² Barnstar
		I feel rather priveleged to come across your images. You have earned a well deserved barnstar Inthedryer (talk) 01:17, 1 May 2015 (UTC)[reply]

Compliments and thanks for this very elegant diagram, which manages to combine both the logical relations as well as depicting the actual shapes. There are some suggestions at File talk:Euler diagram of quadrilateral types.svg where your input would be much appreciated. Thanks! — Sebastian 07:14, 27 April 2015 (UTC)[reply]

Thanks, I'm continuing the discussion there. — Sebastian 18:13, 10 May 2015 (UTC)[reply]

I tried to ungroup this SVG file with no success. I wanted to simplify the image to compare the mirrors of just the TMT and a few others with the scale of the human, excluding the basketball court etc, to make the thumb more easily readable and make a comparative illustration that is directly relevant to secondary sourcing comparisons. Could you help me out? Is there something I need to do to unlock the file in Inkscape before it can be ungrouped? I couldn't figure that out.--Mark Miller (talk) 19:22, 3 May 2015 (UTC)[reply]

Hi, Mark. The SVG was hand-coded and not designed to be edited in Inkscape. If you open the SVG file in a text editor, you'll find that each object has been put in a distinct group, denoted by <g ...> ... </g>. Just delete the groups you don't want, and optionally edit the translate(x,y) values to move the remaining ones around. If you wish to upload it to Wikimedia, please call it a different name instead of overwriting the existing file. Let me know if you need further help. Cheers, cmɢʟee⎆τaʟκ 22:57, 9 May 2015 (UTC)[reply]

Oh yeah, this would be a different image entirely but for now this reminds me that I was discussing this image with Viriditas who felt it should return and I agreed that text could be sourced to make the image more relevant. I forgot all about that so I should re-add the image until we have something more specific. Even then, this has enough consensus to go back.--Mark Miller (talk) 23:05, 9 May 2015 (UTC)[reply]

It's fair that you'd prefer the measurements to be sourced. I had originally obtained them from the telescopes' respective articles. File_talk:Comparison_optical_telescope_primary_mirrors.svg has more sources for the size of their holes. At very least, it's survived some poor-man's peer review by appearing in some notable sites: http://phys.org/news/2015-01-biggest-telescopes-world-space.html , http://www.universetoday.com/118202/what-are-the-biggest-telescopes/ and http://blogs.scientificamerican.com/WSS/post.php?blog=24&post=7677 . On another note, I think having the sports courts is useful as they are standard units people from many countries can relate to. Additionally, a human is so small at this scale that it doesn't provide a useful comparison. Cheers, cmɢʟee⎆τaʟκ 00:02, 10 May 2015 (UTC)[reply]

Hi Cmglee,

I found your page after seeing your bilinear interpolation graph (Bilinear_interpolation_visualisation.svg). I was really impressed with all of your work!

I made a small modification of this file for use during math presentations--only the labels are changed. Are you okay with me using this file, and if so, how would you prefer to be acknowledged? Should there be a link to the original file?

Here's the modified version: http://math.arizona.edu/~gzhelezov/temporary_upload/Bilinear_interpolation_visualisation.pdf

Thanks!

Gleb — Preceding unsigned comment added by 128.196.102.182 (talk) 23:26, 15 May 2015 (UTC)[reply]

Certainly, Gleb, and thanks for your compliments and checking back with me — much appreciated! Based on the examples at http://commons.wikimedia.org/wiki/Commons:Credit_line#CC-BY_and_CC-BY-SA_licenses , you could have

© CMG Lee / http://commons.wikimedia.org/wiki/file:bilinear_interpolation_visualisation.svg / CC-BY-SA-3.0

cmɢʟee⎆τaʟκ 07:18, 17 May 2015 (UTC)[reply]

Hi Cmglee,

We would like to use the linked photo for an internal company presentation to demonstrate the advances in semiconductor fabrication.

https://en.wikipedia.org/wiki/Semiconductor_device_fabrication#/media/File:Comparison_semiconductor_process_nodes.svg

Thank you. — Preceding unsigned comment added by DruceWayne2015 (talk • contribs) 00:47, 19 May 2015 (UTC)[reply]

Sure, Druce. It'd be great if you could add a credit line as follows. Ta, cmɢʟee⎆τaʟκ 22:08, 20 May 2015 (UTC)[reply]

© CMG Lee / http://commons.wikimedia.org/wiki/file:comparison_semiconductor_process_nodes.svg / CC-BY-SA-3.0

Hi Cmglee, I was wondering, if it would be possible to add the Bandra Worli Sea Link to the image? At 5.6km, it is the longest bridge in India, and also the first open sea bridge in the country. --Rsrikanth05 (talk) 12:34, 13 June 2015 (UTC)[reply]

Hi Rsrikanth05, the graphic is already rather cluttered, so I'll consider adding another bridge only if it's historically and globally significant, such as Trajan's Bridge or Constantine's Bridge (Danube). Cheers, cmɢʟee⎆τaʟκ 13:25, 1 July 2015 (UTC)[reply]

Hi, Heap's algorithm had an error in the pseudocode, so your excellent illustration File:Heap_algorithm_with_4_elements.svg is now unfortunately out of date. It would be great if it could be updated. The correct algorithm should use exactly 1 swap between each permutation. sverdrup (talk) 11:51, 29 June 2015 (UTC)[reply]

Hi! That's a shame. Can you please get someone else who is knowledgeable in this to verify that this new algorithm is correct, before I spend extra effort in updating it? Thanks, cmɢʟee⎆τaʟκ 13:33, 1 July 2015 (UTC)[reply]

That's understandable. I've asked for help to review the article, but it's hard to find anyone to do it I think. I've also taken the extreme liberty of producing a successor illustration based on yours, with just the permutations and not the transcript. Hope you think this is ok. I realize I'm not as good as you with svgs and illustrations!, but I wanted to do as well as I could until further improvements are possible. As you can see, the corrected version of the algorithm is much prettier, only one swap between each state. The first sentence in Heap's article from 1963: Methods for obtaining all possible permutations of a number of objects, in which each permutation differs from its predecessor only by the interchange of two of the objects, are discussed. sverdrup (talk) 14:12, 8 July 2015 (UTC)[reply]

Well done on correcting the graphic, Sverdrup. Your version looks excellent and less cluttered without the transcript, so you needn't be modest about your illustration skills! The algorithm is indeed more elegant, so I've taken the liberty to put in colour-coded captions to show the pattern. Thanks for your hard work! Cheers, cmɢʟee⎆τaʟκ 23:12, 10 July 2015 (UTC)[reply]

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Dear Cmglee,

I am a student trying to reproduce Rømer's experiment in working out the speed of light, however I can not find a database with observable (which of course is required as the difference in observable time is what allows us to work out the speed of light) times for the eclipse of J's moon, Io. On the wiki page about the speed of light you have uploaded a picture (at 22:41, 26 April 2014) of distance against time of earth and jupiter, with the time delay written above. I was wondering if you possibly have results that I may use as data for my project. Ideally 226 data points would be amazing (as there are roughly 226 Io eclipses in an earth year) but anything that can be used would be great. That way I can graph the difference in observed eclipse times with actual eclipse times and the difference would hopefully give me the speed of light.

Hope this reaches you and thanks for your time! Adam Hulse — Preceding unsigned comment added by Adaden123 (talk • contribs) 13:29, 6 August 2015 (UTC)[reply]

Dear Adam,

Good to read that you're trying the classic experiment for yourself. To tell you the truth, I simulated the times by assuming that the speed of light was known and calculating backwards to make the graphic.

See if the data at the bottom of http://www.eso.org/public//outreach/eduoff/aol/market/experiments/advanced/skills302.html helps. Alternatively, try http://www.amsmeteors.org/mallama/galilean/timings.html (much more data is available by Googling for "Galilean Satellite Eclipse Timings").

Best wishes in your experiment!
cmɢʟee⎆τaʟκ 20:42, 6 August 2015 (UTC)[reply]

P.S. Since you asked nicely, I've reformatted and cleaned up the data on the ESO page (unfortunately with only minute resolution) to user_talk:cmglee/Io-Jupiter_eclipse_times — good luck!

Dear Cmglee,

Thank you so much for reading my message! However both these links appear to be eclipse times, without the required observable time delay that gives the speed of light. The reason I think it is so hard to find such data is because observable times are impossible to have a whole years worth of data due to readings of eclipses being under the horizon or wrong side of Jupiter. However I was hopeful to find at least two observations (opposite sides of Earths orbit, one closest and one furthers from jupiter) of an event maybe already part of an experiment related to Rømer's calculations.

Again, thank you for your time! Adam Hulse — Preceding unsigned comment added by Adaden123 (talk • contribs) 13:51, 7 August 2015 (UTC)[reply]

Dear Adam,

You're welcome! Indeed, the time delay between the eclipse's actual start/end and its observation on Earth is unknown, but it doesn't matter. The difference in the times of successive starts/ends lets one estimate the speed of light as one can calculate by how much farther/nearer it is from Jupiter as Earth's orbit around the Sun has been established.

A simplistic way of looking at it is to imagine a clock synchronised to the average period of Io. When Earth is at conjunction (farthest from Jupiter), the eclipse is observed 8.3 minutes too late; at opposition (nearest Jupiter), it is 8.3 minutes too early. This implies that it takes 8.3 minutes for light to travel the extra (or reduced) distance i.e. the radius of Earth's orbit around the Sun. If you read through the text on http://www.eso.org/public//outreach/eduoff/aol/market/experiments/advanced/skills302.html , you'll find some formulas and exercises to let you estimate the speed of light using the data in the table.

By the way, you're right that Earthlings can see only the start of eclipses for about half a year, and the end of eclipses for about half a year, but that is sufficient. More explanation is on http://gsjournal.net/Science-Journals/Research%20Papers-Relativity%20Theory/Download/2812 . Good luck!

cmɢʟee⎆τaʟκ 13:00, 8 August 2015 (UTC)[reply]

Hi! I just found SVG animation ☎ 1 Feb 2015. I see that you are interested in SVG also. The only SVG files I made are shown beside; please read [1]. Please take a look at hole page https://test.wikipedia.org/wiki/Most-perfect_magic_square and see what can be used at different languages / pages. I am a bureaucrat at test. If you need admin rights there please let me know. Regards lɛʁi ʁɑjnhɑʁt (Leri Reinhart)
‫·‏לערי ריינהארט‏·‏T‏·‏m‏:‏Th‏·‏T‏·‏email me‏·‏‬ 15:37, 10 August 2015 (UTC)[reply]

FYI: commons:Help desk#today this is a draft · how to improve the SVG file

Regards ‫·‏לערי ריינהארט‏·‏T‏·‏m‏:‏Th‏·‏T‏·‏email me‏·‏‬ 20:19, 10 August 2015 (UTC)[reply]

Hi Leri, Thanks for your messages. Glad you're interested in SVG. Sorry, I don't completely follow what you wrote, as well as the entry at http://test.wikipedia.org/wiki/Most-perfect_magic_square#new_SVG_animations. Did you want me to pick some images from that page to include in magic square articles in the English Wikipedia? cmɢʟee⎆τaʟκ 12:12, 11 August 2015 (UTC)[reply]

Thanks for your change: "The second property above implies that each pair of the integers with the same background colour in the 4×4 square below have the same sum, and hence any 2 such pairs sum to the magic constant." These are 8x7/2=28 sets of four cells, if you add the 16 2x2 subsquares (including the broken ones), the four rows and the four columns you will have 52 subsets with the same sum 34 and used at a geometric shape which can be shifted using wrap around technics. Please note that these patterns are independent of the content of the used square. Please note that 5, 7, 9 and 13 also sums to 34. However if this pattern is shifted the sum changes.
At test I collected many items (and links) related to the most perfect magic squares. Before adding step by step some items we should clarify the names used for these type of squares.
The SVG animations will come at the end of the work. They should mainly relate to transformations and constructions.

FYI: If you interpret / see / define the replacement of the cells from one square M_i to another square M₀ you will get a matrix which can be used for the transformation of any of the 384 squares. This operation and the set of squares define a non communicative group with the transformation from (any) arbitrary chosen M₀ to M₀ as the group identity. The transformation replacing each cell with its complement located at a diagonal offset of n/2 is a special transformation which forms the commutative core together with the identity transformation.
It is interesting that the transformations do not map any arbitrary combination of the 52 sets to subsets. The 8 diagonals and the 4 geometric pattern similar to that formed by a_1,1, a_1,3, a_3,1 and a_3,3 form a 12 element subset which will be mapped into itself. While the Frénicle standard form preserves orthogonality it should be noted that any 2x2 subsquare may be transformed to another 2x2 subsquare, to a row or to a column. I have some videos on this (file:Rakonto 09 deu.ogv in German).
2007 I created at meta nested templates for all transformations. I could identify a subgroup of the 384 transfoormations homeomorph with the basic (eight element) quaternion subgroup: ±1, ±i, ±j, ±k . At m:Meta:Requests for deletion#multiscript_collaboration I asked for the undeletion of that work. +1 corresponds ro the identity and -1 to the complement.
2009 I created some videos about transformations which I will upload as OGG files to c:Commons:Story (game) - multilingual interdisciplinary collaborative work#Media (examples).
Are you using skype? Regards ‫·‏לערי ריינהארט‏·‏T‏·‏m‏:‏Th‏·‏T‏·‏email me‏·‏‬ 17:50, 11 August 2015 (UTC)[reply]

Hi Cmglee! file:PanmagicSquare-Order4.svg|111x121px may replace file:PanmagicSquare-Order4.png. Can you please add the required info to the ping file? Thanks in advance! ‫·‏לערי ריינהארט‏·‏T‏·‏m‏:‏Th‏·‏T‏·‏email me‏·‏‬ 20:19, 12 August 2015 (UTC)[reply]

Thanks, לערי ריינהארט. That's quite detailed analysis above. It's beyond my maths knowledge to evaluate, but it seems quite reasonable. Can you update the magic square or most-complete magic square page (with references) and let's see what other editors think of it?

I'd rather keep the discussion on Wikipedia, if you don't mind.

Lastly, I'm unsure what "required info" you want added to the PNG file. Since you've created the SVG, the PNG can be obsoleted so it probably needn't be updated already.

Cheers, cmɢʟee⎆τaʟκ 00:27, 17 August 2015 (UTC)[reply]

Hi Cmglee!

I am considering to use one of your drawing (https://commons.wikimedia.org/wiki/File:Lego_dimensions.svg) in a book that I am writing on Distributed Simulation (http://www.springer.com/de/book/9783319030494). I would like to kindly send you a permission form. Will you be kind enough to contact me at umutdurak [at] gmail.com?

Many thanks! — Preceding unsigned comment added by Umutdurak (talk • contribs) 22:48, 15 August 2015 (UTC)[reply]

Hi, Umutdurak. You can freely reuse the drawing as long as you add the credit line below; no permission form is needed :-) Ta, cmɢʟee⎆τaʟκ 00:33, 17 August 2015 (UTC)[reply]

© CMG Lee / http://commons.wikimedia.org/wiki/file:Lego_dimensions.svg / CC-BY-SA-3.0

Hi,
You appear to be eligible to vote in the current Arbitration Committee election. The Arbitration Committee is the panel of editors responsible for conducting the Wikipedia arbitration process. It has the authority to enact binding solutions for disputes between editors, primarily related to serious behavioural issues that the community has been unable to resolve. This includes the ability to impose site bans, topic bans, editing restrictions, and other measures needed to maintain our editing environment. The arbitration policy describes the Committee's roles and responsibilities in greater detail. If you wish to participate, you are welcome to review the candidates' statements and submit your choices on the voting page. For the Election committee, MediaWiki message delivery (talk) 13:09, 23 November 2015 (UTC)[reply]

Hi,
You appear to be eligible to vote in the current Arbitration Committee election. The Arbitration Committee is the panel of editors responsible for conducting the Wikipedia arbitration process. It has the authority to enact binding solutions for disputes between editors, primarily related to serious behavioural issues that the community has been unable to resolve. This includes the ability to impose site bans, topic bans, editing restrictions, and other measures needed to maintain our editing environment. The arbitration policy describes the Committee's roles and responsibilities in greater detail. If you wish to participate, you are welcome to review the candidates' statements and submit your choices on the voting page. For the Election committee, MediaWiki message delivery (talk) 13:32, 23 November 2015 (UTC)[reply]

This query is for San Francisco items without image. Charles Matthews (talk) 17:03, 28 November 2015 (UTC)[reply]

Hello CMG Lee, I'd like to use your satellite orbit diagram on a scientific poster at the American Geophysical Union's Fall 2015 meeting. The poster describes the use of GNSS systems beyond GPS to collect more accurate scientific geodetic data. The poster will appear online and in a single print copy onsite. I currently have the following as a credit line under the image: © CMG Lee / Wikimedia Commons / CC-BY-SA-3.0 I wanted to make sure that usage and credit would be acceptable. Cheers. Myowncompass (talk) —Preceding undated comment added 01:27, 3 December 2015 (UTC)[reply]

Hello, Myowncompass ☺ Certainly! The credit line is fine, too. If you wouldn't mind, could you please link me to an online version of your poster? Thanks, cmɢʟee⎆τaʟκ 13:13, 3 December 2015 (UTC)[reply]

Hello Cmglee,

Thanks for making the interesting sankey for this subject. I didn't know about sankey diagrams before. Very cool!

You probably know this, but if not, even diagrams need WP:RS citation. Unless rules changed the last few years it is enough to include the cites in the image file; repeating the cites in the caption on any particular article is optional.

In the case at hand, it looks like you used numbers from the source listed in a section of the article. Rats.... the source appears to be not RS since it is a blog which does not show its own sources. In addition, the entire section of the article next to your diagram is plagiarized from that blog, so the text needs to be redone in any case.

Very cool way to show the energy budget, if we can source it correctly

NewsAndEventsGuy (talk) 13:04, 8 December 2015 (UTC)[reply]

Hello NewsAndEventsGuy,

Thanks for your observation and compliments. Since you retained the text and graphic until it could be resolved — and asked so nicely — I've managed to source the data and rewrite it as follows.

How is it now? cmɢʟee⎆τaʟκ 14:36, 9 December 2015 (UTC)[reply]

At causal glance and cursory contemplation it looks great; try it out.... and thanks. NewsAndEventsGuy (talk) 19:37, 9 December 2015 (UTC)[reply]

def get_key(p1,q1, p2,q2): return p1 * MAX * MAX * MAX + q1 * MAX * MAX + p2 * MAX + q2
MIN = 0; MAX = 4
# MIN = 1; MAX = 7
low = max(MIN, 1)
seen = {}
for         qb1 in range(low, MAX + 1):
 for        qb2 in range(low, MAX + 1):
  for       ql1 in range(low, MAX + 1):
   for      ql2 in range(low, MAX + 1):
    # if (qb1 + qb2 == ql1 + ql2):
     for    pb1 in range(MIN, qb1 + 1):
      for   pb2 in range(MIN, qb2 + 1):
       for  pl1 in range(MIN, ql1 + 1):
        for pl2 in range(MIN, ql2 + 1):
         seen[   get_key(pb1,qb1, pl1,ql1)] = True
         if (not get_key(pb2,qb2, pl2,ql2) in seen and
             float(pb1) / qb1 > float(pl1) / ql1 and float(pb2) / qb2 > float(pl2) / ql2 and
             float(pb1 + pb2) / (qb1 + qb2) < float(pl1 + pl2) / (ql1 + ql2)):
          print('%d/%d > %d/%d and %d/%d > %d/%d but %d/%d < %d/%d' %
                (pb1,qb1, pl1,ql1, pb2,qb2, pl2,ql2, pb1+pb2,qb1+qb2, pl1+pl2,ql1+ql2))

1/1 > 3/4 and 1/3 > 0/1 but 2/4 < 3/5
1/1 > 2/3 and 1/4 > 0/1 but 2/5 < 2/4
1/1 > 3/4 and 1/4 > 0/1 but 2/5 < 3/5
1/1 > 3/4 and 1/4 > 0/2 but 2/5 < 3/6
1/1 > 3/4 and 1/4 > 0/3 but 2/5 < 3/7
2/2 > 3/4 and 1/4 > 0/1 but 3/6 < 3/5
3/3 > 3/4 and 1/4 > 0/1 but 4/7 < 3/5